Chapters
Exercise 1
Solve:
Exercise 2
Solve:
Exercise 3
Solve:
Exercise 4
Calculate the values of k for which the roots of the equation x² − 6x + k = 0 are two real and distinct numbers.
Exercise 5
Solve:
1
2
3
Exercise 6
Solve:
Exercise 7
Solve:
1
2
3
Solution of exercise 1
Solve:
Solution of exercise 2
Solve:
4x² − 4x + 1 ≤ 0
4x² − 4x + 1 = 0
Solution of exercise 3
Solve:
The numerator is always positive.
The denominator cannot be zero.
Therefore, the original inequality will be equivalent to:
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Solution of exercise 4
Calculate the values of k for which the roots of the equation are two real and distinct numbers.
Solution of exercise 5
Solve:
1
2
3
Solution of exercise 6
Solve:
Solution of exercise 7
Solve:
1
As the first factor is always positive, consider the sign of the 2nd factor.
2
3
The second factor is always positive and nonzero, therefor, only consider the sign of the 1st factor.
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