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Let's go

Exercise 1

Solve:

Exercise 2

Solve:

Exercise 3

Solve:

Exercise 4

Calculate the values of k for which the roots of the equation x² − 6x + k = 0 are two real and distinct numbers.

Exercise 5

Solve:

 

2

 

Exercise 6

Solve:

 

Exercise 7

Solve:

 

Solution of exercise 1

Solve:

 

Solution of exercise 2

Solve:

4x² − 4x + 1 ≤ 0

4x² − 4x + 1 = 0

 

Solution of exercise 3

Solve:

 

    The numerator is always positive.

The denominator cannot be zero.

Therefore, the original inequality will be equivalent to:

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Solution of exercise 4

Calculate the values of k for which the roots of the equation   are two real and distinct numbers.

 

Solution of exercise 5

Solve:

2

       

       

     

 

Solution of exercise 6

Solve:

         

 

Solution of exercise 7

Solve:

As the first factor is always positive, consider the sign of the 2nd factor.

 

 

The second factor is always positive and nonzero, therefor, only consider the sign of the 1st factor.

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Emma

Emma

I am passionate about travelling and currently live and work in Paris. I like to spend my time reading, gardening, running, learning languages and exploring new places.