Optimization of resources (cost and time) is required in every aspect of our lives. We need the optimization because we have limited time and cost resources, and we need to take the maximum out of them. Every aspect of the business world today requires optimization, from manufacturing to resolving supply chain issues to stay competitive.

Linear programming offers the easiest way to do optimization as it simplifies the constraints and helps to reach a viable solution to a complex problem. In this article, we will solve some of the linear programming problems through the graphing method.

 

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Exercise 1

A transport company has two types of trucks, Type A and Type B. Type A has a refrigerated capacity of and a non-refrigerated capacity of . In contrast, Type B has the same overall volume with equal refrigerated and non-refrigerated stock sections. A grocer must hire trucks to transport of refrigerated stock and of non-refrigerated stock. The cost per kilometre of Type A is , and for Type B. How many trucks of each type should the grocer rent to achieve the minimum total cost?

Exercise 2

A school is preparing a trip for 400 students. The transportation company has 10 buses of 50 seats each and 8 buses of 40 seats but only has 9 drivers available. The rental cost for a large bus is and for a small bus. Calculate how many buses of each type should be used for the trip for the least possible cost.

Exercise 3

A store wants to liquidate 200 shirts and 100 pairs of pants from last season. They have decided to put together two offers, A and B. Offer A is a package of one shirt and a couple of pants which will sell for . Offer B is a package of three shirts and a pair of pants, which will sell for . The store does not want to sell less than 20 packages of Offer A and less than 10 of Offer B. How many boxes do they have to deal with to maximize the money generated from the promotion?

 

 

Solution of Exercise 1

A transport company has two types of trucks, Type A and Type B. Type A has a refrigerated capacity of and a non-refrigerated capacity of . In contrast, Type B has the same overall volume with equal refrigerated and non-refrigerated stock sections. A grocer must hire trucks to transport of refrigerated stock and of non-refrigerated stock. The cost per kilometre of Type A is , and for Type B. How many trucks of each type should the grocer rent to achieve the minimum total cost?

a) Choose the unknowns.

x = Type A trucks

y = Type B trucks

b) Write the objective function.

c) Write the constraints as a system of inequalities.

d) Find the set of feasible solutions that graphically represent the constraints.

e) Calculate the coordinates of the vertices from the compound of feasible solutions.

f) Calculate the value of the objective function at each vertex to determine which has the maximum or minimum values.

As x and y must be natural numbers round the value of y.

By default, we see what takes the value x to y = 66 in the equation , which is within the feasible solutions.

The minimum cost is . To achieve this 51 trucks of Type A and 66 trucks of Type B are needed.

 

Solution of exercise 2

A school is preparing a trip for 400 students. The company who is providing the transportation has 10 buses of 50 seats each and 8 buses of 40 seats, but only has 9 drivers available. The rental cost for a large bus is and for a small bus. Calculate how many buses of each type should be used for the trip for the least possible cost.

a)Choose the unknowns.

x = small buses

y = big buses

b) Write the objective function.

c) Write the constraints as a system of inequalities.

d)  Find the set of feasible solutions that graphically represent the constraints.

Example 2 - part d

e)  Calculate the coordinates of the vertices from the compound of feasible solutions.

Example 2 - part e

f)  Calculate the value of the objective function at each vertex to determine which has the maximum or minimum values.

Hence, the minimum cost is . This is achieved with 4 large and 5 small buses.

We substituted the points (0,9), (0,8), and (5,4) in the equation to determine the minimum cost. However, you can tell this by directly looking at the graph. The coordinate (5,4) comes under the feasible region and is the minimum point of it.

 

Solution of exercise 3

A store wants to liquidate 200 shirts and 100 pairs of pants from last season. They have decided to put together two offers, A and B. Offer A is a package of one shirt and a pair of pants which will sell for . Offer B is a package of three shirts and a pair of pants, which will sell for . The store does not want to sell less than 20 packages of Offer A and less than 10 of Offer B. How many packages of each do they have to deal to maximize the money generated from the promotion?

a) Choose the unknowns.

x = number of packages of Offer A

y = number of packages of Offer B

b) Write the objective function.

c) Write the constraints as a system of inequalities.

d) Find the set of feasible solutions that graphically represent the constraints.

Example 3 - part d

e)  Calculate the coordinates of the vertices from the compound of feasible solutions.

Example 3 - part e

f) Calculate the value of the objective function at each vertices to determine which has the maximum or minimum values.

50 packages of each offer generate a maximum of  in sales.

 

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Emma

Emma

I am passionate about travelling and currently live and work in Paris. I like to spend my time reading, gardening, running, learning languages and exploring new places.